Matematika

Pertanyaan

Diberikan dua buah fungsi a. (Fog) (x) =3x²+4x+1 b. G (x) =6 tentukan a. (Fog) (x) b. (Gof) (2) c. (Gof) (x) d. (Gof) (5)

2 Jawaban

  • a.
    f o g (x) = f(g(x)) = f(6x)
    f o g (x) = 3(6x)² + 4(6x) + 1
    f o g (x) = 108x² + 24x + 1

    c.
    g o f (x) = g(f(x)) = g(3x² + 4x + 1)
    g o f (x) = 6(3x² + 4x + 1)
    g o f (x) = 18x² + 24x + 6

    b.
    g o f (2) = 18(2)² + 24(2) + 6
    g o f (2) = 72 + 48 + 6
    g o f (2) = 126

    d.
    g o f (5) = 18(5)² + 24(5) + 6
    g o f (5) = 450 + 120 + 6
    g o f (5) = 576
  • Yang A
    Fog = 3 (6²) + 4 ( 6 ) + 1
    = 3 ( 36 ) + 24+ 1
    = 108 + 24 + 1
    = 133

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