Diketahui F : R -> dan g : R -> dirumuskan oleh f(x) = 3x + 4 dan g(x) = 2 - x. Rumus untuk ( g¤f )^-1 (x) =.... a. 1/3 (2-x) b. 1/3 (10-x) c. 1/3 (2-3x) d. -1/

(gof) ^-1 (x) = (f^-1 o g^-1).

f (x) = 3x + 4
3x + 4 = y
y - 4 = 3x
y - 4 / 3 = x
x - 4 / 3 = f (x)^-1.

g (x) = 2 - x
2 - x = y
y - 2 = x
x - 2 = g (x)^-1.

(f^-1 o g^-1) = (x - 2) - 4 /3
= x - 6 /3.

Jangan lupa jadikan jawaban yang terbrainly.

f (x) = 3x + 4 dan g(x) = 2 - x
gof (x) = g { f (x) }
g (3x +4)
= 2 -(3x +4)
= 2 -3x -4
= -3x -2
misal y = gof (x)
y = -3x -2
3x = -y - 2
x = (-y -2) / 3
f-1(x) = (-x -2)/3
f -1(x) = - (x +2)/3
f-1(x) = -1/3(x +2)...( d)