Diketahui f(x) = 4 - x². Jika daerah asal f adalah df = {x | -4 < x ≤ 3, x anggota R}, daerah hasil fungsi y = |f(x)| adalah..... Tolong bantu yhaa

jawab

fungsi

f(x) = |4 - x²|

daerah x ={-3,-2, -1, 0 , 1, 2, 3}
daerah hasil
x = - 3 --> f(-3) = |4 - (-3)²| = |4 - 9| = 5
x = - 2 --> f(-2) = |4 - (-2)²| = |4 - 4| = 0
x = - 1 --> f(-1) = |4 - (-1)²| = |4 - 1| = 3
x = 0  -->  f(0) = |4 - (0)| = |4 - 0| = 4
x = 1 --> f(1) = |4 - (1)²| = |4 - 1| = 3
x = 2 --> f(2)= |4 - (2)²| = |4 - 4| = 0
x = 3 --> f(3) = |4 - (3)²|= |4 -9| = 5

daerah hasil  0 ≤ f(x) ≤ 5