5akar3 x 3akar5= 10akar7 x akar7= akar5 (3akar5 - 5)= 3akar6(6+akar6)= (akar5 - 3)(akar2+7)= (2akar7+5) (3akar7-2)= (3+akar6)²= (3 + akar2) (3 - akar2)= (5akar2
Matematika
Deakn
Pertanyaan
5akar3 x 3akar5=
10akar7 x akar7=
akar5 (3akar5 - 5)=
3akar6(6+akar6)=
(akar5 - 3)(akar2+7)=
(2akar7+5) (3akar7-2)=
(3+akar6)²=
(3 + akar2) (3 - akar2)=
(5akar2 - 3) ( 5akar2 + 3)=
10akar7 x akar7=
akar5 (3akar5 - 5)=
3akar6(6+akar6)=
(akar5 - 3)(akar2+7)=
(2akar7+5) (3akar7-2)=
(3+akar6)²=
(3 + akar2) (3 - akar2)=
(5akar2 - 3) ( 5akar2 + 3)=
