Matematika

Pertanyaan

mohon djwb kumpulin besok
mohon djwb kumpulin besok

2 Jawaban

  • berusahalah mengerjakan sendiri terlebih dulu sebelum meminta bantuan.
  • 1.) cos 75° = cos (30° + 45°)
    cos 75° = (cos 30°.cos 45°) - (sin 30°.sin 45°)
    cos 75° = (1/2√3)(1/2.√2) - (1/2)(1/2.√2)
    cos 75° = (1/4.√6) - (1/4√2)
    cos 75° = 1/4 (√6 - √2)

    2.) sin 300 = sin (360-300)
    = - sin 60
    = - 1/2 √3

    3.) -2 - √3 (D)

    4.) cos(90-a) = √3 cos a
    sin a = √3 cos a
    sin a/cos a = √3
    tan a = √3 (D)

    5.) tan A = y/x = 2/3
    x = 3
    y = 2
    r = √x² + y²
    r = √3² + 2²
    r = √9 + 4
    r = √13

    sin A = y/r
    = 2/√13
    = 2/13 √13

    cos A = x/r
    = 3/√13
    = 3/13 √13

    sin 2A = 2 sin A. cos A
    = 2 (2/13 √13)(3/13 √13)
    = 156/169
    = 12/13

    7.) sin a = 3/5 , maka cos a = 4/5

    karna di kuadran II cos bernilai negatif sehingga cos a = 4/5

    maka :
    sin 2a = 2 sin a cos a
    = 2 (3/5) (4/5)
    = 24/25

    8.) sin a = 3/5, cos a = 4/5
    sin b = 7/25 , maka cos a = 24/25

    cos (a-b) = cosAcosB + sinAsinB
    = 4/5 × 24/25 + 3/5 × 7/5
    = 96/125 + 21/125
    = 117/125