Nilai dari 9log27 + 3log9+2log8

^9 log 27 + ³log 9 + ²log 8
= ^(3²) log 3³ + ³log 3² + ²log 2³
= (3/2) . ³log 3 + 2 . ³log 3 + 3 . ²log 2
= (3/2) + 2 + 3
= (3/2) + 5
= 13/2

Jawabannya:

Mapel. : Matematika
Bab. : Logaritma

Pembahasan:

9 log 27 + 3 log 9 + 2 log 8
= 3² log 3³ + 3 log 9 + 2 log 8
= 3/2. 3 log 3 + 3 log 3² + 2 log 2³
= 3/2. 1 + 3 log 3² + 2 log 2³
= 3/2 + 2. 3 log 3 + 3. 2 log 2
= 3/2 + 2. 1 + 3. 1
= 3/2 + 2 + 3
= 3/2 + 4/2 + 3
= 7/2 + 6/2
= 13/2
= 6 1/2
Atau
= 6,5

# Maaf Kalo Salah