DiKetahui f(×)=2×+5/3×-1;x tidak boleh sama dengan 1/3.jikaf^-1(a)=-4/5,nilai a=

- Invers Fungsi -

f(x) = (2x+5)/(3x-1)
y = (2x+5)/(3x-1)
y(3x-1) = 2x+5
3xy-y = 2x+5
3xy-2x = 5+y
x(3y-2) = 5+y
x = (5+y)/(3y-2)
f-¹(x) = (5+y)/(3y-2)
f-¹(x) = (5+x)/(3x-2)

f-¹(2) = (5+a)/(3a-2)
-4/5 = (5+a)/(3a-2)
5(5+a) = -4(3a-2)
25+5a = -12a+8
5a+12a = 8-25
17a = -17
a = -1

semoga membantu
-vin