tentukan invers dari fungsi

jawab
fungsi invers

1.
g(x)=  x² - 2x + 1
x² -2x = y - 1
(x - 1)² = y - 1 + 1
(x - 1)² = y
x - 1= √y
x = √y  + 1
g⁻¹ (x)= √x  + 1

2.
f (x) = 2 + ³log x
y = 2 + ³log x
³log x =  y- 2
x = (3)^(y-2)

f⁻¹(x)= (3)ˣ⁻²

3. 
f(x) = 1 + √( x+2)
√(x +2) = y- 1
(x + 2) = (y-1)²
x = 2 - (y-1)²

f⁻¹ (x)= 2 - (x -1)²

4)
g(x)= 1/4 x - 1/2
4 y = x - 2
x = 4y + 2
g⁻¹ (x)=  4x + 2

5)
f(x)= ³log (x- 2)
³log (x - 2) =y
(x - 2) = 3^y
x = 3^y  + 2
f⁻¹ (x) = 3ˣ + 2