Tentukan titik balik fungsi fungsi berikut! A. F(x) = -1/2x^2 + 2/3x - 3/4 Tolong dibantu yaa
Matematika
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Pertanyaan
Tentukan titik balik fungsi fungsi berikut!
A. F(x) = -1/2x^2 + 2/3x - 3/4
Tolong dibantu yaa
A. F(x) = -1/2x^2 + 2/3x - 3/4
Tolong dibantu yaa
2 Jawaban
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1. Jawaban aurigafdl
f(x) = -1/2x² + 2/3x - 3/4
a= -1/2 , b=2/3 , c=-3/4
titik balik fungsi--> (-b/2a , -D/4a)
D= b²-4ac
= ((2/3)² - 4(-1/2)(-3/4)
= 4/9 - (-2)(-3/4)
= 4/9 - 3/2
= 8-27/18
= -19/18
((-2/3 / 2(-1/2) , -(-19/18))
((-2/3 /-2) , (19/-18))
titik balik--> (4/3 , 19/-18) atau (4,19/-6)
#cmiiw -
2. Jawaban dhimascilacap01
f(x) = -1/2x² + 2/3x - 3/4
a= -1/2 , b=2/3 , c=-3/4
titik balik fungsi--> (-b/2a , -D/4a)
D= b²-4ac
= ((2/3)² - 4(-1/2)(-3/4)
= 4/9 - (-2)(-3/4)
= 4/9 - 3/2
= 8-27/18
= -19/18
((-2/3 / 2(-1/2) , -(-19/18))
((-2/3 /-2) , (19/-18))
titik balik--> (4/3 , 19/-18) atau (4,19/-6)