[tex] \sqrt{ 4 - 2x} < \sqrt{3x - 24} [/tex]
Matematika
ulan161
Pertanyaan
[tex] \sqrt{ 4 - 2x} < \sqrt{3x - 24} [/tex]
1 Jawaban
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1. Jawaban mutiaradzandini18
[tex] \sqrt{4 - 2x} < \sqrt{3x - 24} \\ 4 - 2x < 3x - 24 \\ 4 + 24 < 3x + 2x \\ 28 < 5x \\ \frac{28 }{5} < x[/tex]