tolong bantu aku teman teman semuanya itu baru itu ada lagi

rumus phytagoras
no 18
[tex] {24}^{2} = {x}^{2} + {x}^{2} \\ 576 = {2x}^{2} \\ \frac{576}{2} = {x}^{2} \\ \sqrt{288} = x \\ 12 \sqrt{2} = x[/tex]
jawabannya b 12√2
[tex] \frac{qs}{qr} = \sin( \alpha ) \\ \frac{3}{x} = \sin(60) \\ \frac{3}{x} = \frac{ \sqrt{3} }{2} \\ 3 \times 2 = \sqrt{3 } \times x \\ 6 = \sqrt{3} x \\ \frac{6 }{ \sqrt{3} } = x \\ 2 \sqrt{3} = x[/tex]
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jawabannya 4 cm
no 20

[tex] \frac{t}{12} = \sin(60) \\ \frac{t}{12} = \frac{ \sqrt{3} }{2} \\ t \times 2 = \sqrt{3} \times 12 \\ 2t = 12 \sqrt{3} \\ t = \frac{12 \sqrt{3} }{2} \\ t = 6 \sqrt{3} [/tex]
[tex]luas = a \times t \\ = 15 \times6 \sqrt{3} = 90 \sqrt{3} [/tex]