Jawablah dua pertanyaan tersebut dengan menggunakan caranya tolong ya hari senin di kumpulin???

(2) pertama-tama kita cari besar sudutnya dulu
Pj busur = x/360° × K lingkaran
22 = x/360° × 2πr
22 = x/360° × 2 . 22/7 . 21
22 = x/360° × 44/7 . 21
22 = x/360° × 924/7
22 . 7/924 = x/360°
154/924= x/360°
924x = 154 × 360°
924x = 55440°
x = 55440/924
x = 60°

Lalu, kita tinggal mencari Luas juring ya
L juring = 60°/360° × Luas lingkaran
= 1/6 × πr²
= 1/6 × 22/7 . 21 . 21
= 1/6 × 66 . 21
= 1/6 × 1386
= 231 cm²

(3) L tembereng = L juring - L segitiga
= 90°/360° × πr² - 1/2 ×a×t
= 1/4 × 3,14 . 20 . 20 - 1/2 × 20 × 20
= 1/4 × 1256 - 200
= 314 - 200
= 114 cm²