Nilai 5 xy yg memenuhi sistem persamaan linear x+y=7 dan 7x+3y=37

x+y=7 (dikali 3) 3x + 3y = 21
7x+3y=37 (dikali 1) 7x + 3y=37

3x + 3y = 21
7x + 3y = 37
------------------(dikurangi)
-4x = -16
x = -16/-4 = 4

x + y = 7
y = 7 - x = 7 - 4 = 3

5xy = 5(4)(3) = 60

X+y =7
7X+3y=37

7X+7y=49
7X+3y=37
4y=12
y=3
X+y =7
X+3 =7
X= 4

Jadi 5xy
=5×4×3
=60