-2xkuadrat + 11x - 28 = 0 Tolong cari pemfaktorannya

[tex]2x {}^{2} + 11x - 28 = 0 \\ a \frac{}{} = 2 \: \: \\ b = 11 \\ c = - 28 \\ x1 = \frac{ - 11 - \sqrt{11 {}^{2} - 4 \times 2 \times( - 28)} }{ 2 \times 2} = \\ \frac{ - 11 - \sqrt{121 + 224} }{4} = \frac{ - 11 - \sqrt{345} }{4 } \\ x2 = \frac{ - 11 + \sqrt{11 {}^{2} - 4 \times 2 \times ( - 28)} }{2 \times 2} = \\ \frac{ - 11 + \sqrt{121 + 224} }{4} = \frac{ - 11 + \sqrt{345} }{4} [/tex]
semoga membantu kalau ada yg belum di mengerti tanya di komentar