Turunan fungsi. Jawaban dari soal ini f(×)=(×^5-1)(×^6+3×^2+2×)
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Pertanyaan
Turunan fungsi. Jawaban dari soal ini f(×)=(×^5-1)(×^6+3×^2+2×)
2 Jawaban
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1. Jawaban Solihinajah703
Jadi f'(x) = 11x^10 +21x^6+6x^5-6x-22. Jawaban farras0
f(×)=(×^5-1)(×^6+3×^2+2×)
f'(x) = u' dikali v + u dikali v'
*u' = (×^5-1) = 5x^4
*v' = (×^6+3×^2+2×) = 6x^5 +6x+2
f'(x) = (5x^4) dikali (×^6+3×^2+2×) + (×^5-1) dikali (6x^5 +6x+2)
= 5x^10 +15x^6 +10x^5 +6x^10 +6x^6 +2x^5 -6x^5 -6x-1
= 11x^10 +21x^6 +6x^5 -6x-2Pertanyaan Lainnya