Matematika

Pertanyaan

Turunan fungsi. Jawaban dari soal ini f(×)=(×^5-1)(×^6+3×^2+2×)

2 Jawaban

  • Jadi f'(x) = 11x^10 +21x^6+6x^5-6x-2
    Gambar lampiran jawaban Solihinajah703
  • f(×)=(×^5-1)(×^6+3×^2+2×)
    f'(x) = u' dikali v + u dikali v'
    *u' =
    (×^5-1) = 5x^4
    *v' =
    (×^6+3×^2+2×) = 6x^5 +6x+2
    f'(x) =
    (5x^4) dikali (×^6+3×^2+2×) + (×^5-1) dikali (6x^5 +6x+2)
           = 5x^10 +15x^6 +10x^5 +6x^10 +6x^6 +2x^5 -6x^5 -6x-1
           = 11x^10 +21x^6 +6x^5 -6x-2

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