Cos (A+B) = 1/2 dan Sin (A-B) = 1/2, 0° < (A + B) ≤ 90° dan A > B maka Sin A dan Cos A adalah? #bantujawab

[tex] \cos( \alpha + \beta ) = \frac{1}{2} \\ \cos( \alpha + \beta ) = arc \: \cos(60) \\ a + \beta = 60[/tex]
[tex] \sin( \alpha - \beta ) = \frac{1}{2} \\ \sin( \alpha - \beta ) = arc \: \sin(30) \\ \alpha - \beta = 30[/tex]
[tex] \alpha + \beta = 60 \\ \alpha - \beta = 30[/tex]
------------------------- +
[tex]2 \alpha = 90 \\ \alpha = 45[/tex]
[tex] \alpha + \beta = 60 \\ 45 + \beta = 60 \\ \beta = 60 - 45 \\ \beta = 15[/tex]

[tex] \sin( \alpha ) = \sin(45 ) = \frac{1}{2} \sqrt{2} \\ \cos( \beta ) = [/tex]