jawab ya .. turunan fungsi kelas 11.

penjelasan nya lihat d gambar ya

[tex]y = \frac{4 {x}^{2} + 1 }{x - 1} \\ {y}^{'} = \frac{u 'v - uv '}{v^{2} } \\ {y}^{'} = \frac{8x (x - 1) -( (4 { {x}^{2} + 1} )(1))}{(x - 1)^{2} } \\ {y}^{'} = \frac{8x {}^{2} - 8x- {4x}^{2} - 1}{ {(x - 1)( \times - 1)}} \\ = \frac{ {4x}^{2} - 8x - 1}{({x}^{2} - 2x + 1 )} [/tex]

y' = n u^n-1 u'
y' = 3(2x+5)(x^2+5x-24)^2
y' = (6x+15)(x^2+5x-24)^2

klo no.5 sih mending gk usah dijabarin, yg ada malah pusing. dibiarin gtu aja sih dah cukup.