Nilai dari 2log12- 2log5 - 2log3 + 2log20 adalah

²log2² x 3-²log5-²log3+²log2²x5=
2 ²log3 - ²log5-²log3+2²log5
2+2=4

Ingat rumusnya !
ᵃlogb - ᵃlogc = ᵃlog(b/c)
ᵃlogb + ᵃlogc = ᵃlog(b . c)
ᵃlogbˣ = x . ᵃlogb
ᵃloga = 1

Penyelesaian:
²log12 - ²log5 - ²log3 + ²log20
= ²log(12/5) - ²log3 + ²log20
= ²log2,4 - ²log3 + ²log20
= ²log(2,4/3) + ²log20
= ²log0,8 + ²log20
= ²log(0,8 . 20)
= ²log16
= ²log2⁴
= 4 . ²log2
= 4 . 1
= 4