tolong jawab yaa.. Thx

panjang BC =
[tex] \sqrt{ {39}^{2} - {36}^{2} } = \sqrt{225} = 15[/tex]
jadi panjang BC adalah 15.
a. sin b = BC/AC= 15/39
b. cos b = AB/AC = 36/39
c. tan b = BC/AB= 15/36
d. cosec b = 39/15
e. sec b = 39/36
f. cotan b = 36/15