tolong bantu jawab ya teman2. butuh sekarang. yg nomor 4 aja

d=10 cm
r=1\2X10=5 cm
t=12 cm
s²=r²+t²
=5²+12²
=125+144
s²=169
s=√169
=13
a.luas selimut kerucut=Πrs
=3,14×5×13=204,1 cm
b.luas kerucut=Πr(r+s)
=3,14×5(5+13)=3,14×5×18=282,6 cm²
c.volume kerucut=1/3Πr³t
=1/3×3,14×5³×12=3,14×125×4=1570cm³