jika panjang AB = 30 cm BC = 23 cm DC = 24 cm dan EF = 5 cm maka keliling daerah yang diarsir adalah

[tex]l = \frac{(a + b) \times t}{2} \\ l = \frac{(23 + b) \times 24}{2} \\ b = 24 \times 2 - 23 \\ b = 48 - 23 \\ b = 25[/tex]
DF=24:2=12
[tex]ed = \sqrt{ {5}^{2} + {12}^{2} } \\ ed = \sqrt{25 + 144} \\ ed= \sqrt{169} \\ ed= 13[/tex]
[tex]30 + 23 +25 +13(2) = 53+25 + 26 = 104 [/tex]