dik fungsi f(x) =x+6 dan g(x) = x+ 10 tent 1 (f-g) (x) 2 (g¤f) (x) 3 f invers (x) 4 g invers (x) 5 (g¤f) invers (x) nb ¤ bundaran

1.
(f - g)(x) = f(x) - g(x)

x + 6 - x + 10 = (f - g)(x)
16 = (f - g)(x)

2.
(g • f)(x) = g(f(x))

(x + 6) + 10 = g(f(x))
x + 16 = g(f(x))

3.
f(x) = y

y = x + 6
x = y - 6
f'(x) = x - 6

4.
g'(x) = y

y = x + 10
x = y - 10
g'(x) = x - 10

5.
(g • f)'(x) = g'(f'(x))

(x - 6) - 10 = (g • f)(x)
x - 16 = (g • f)(x)