Metode eliminas idari 3c+2d =8dan1/3(c+6)-1/2d=0

3c + 2d = 8 ....... (1)

1/3 (c + 6) - 1/2 d = 0
1/3 c + 1/3 x 6 - 1/2 d = 0
1/3 c + 2 - 1/2 d = 0
1/3 c - 1/2 d = -2 ...... (2)

Eliminasi (1) dan (2)
3c + 2d = 8
1/3 c - 1/2 d = -2 x4
------------------------
3c + 2d = 8
4/3 c - 2d = -8
------------------------ +
13/3 c = 0
c = 0

Substitusi c ke (1) atau (2)
3c + 2d = 8
3.0 + 2d = 8
0 + 2d = 8
2d = 8
d = 4

Jadi c = 0 dan d = 4.