[tex](x.y ^{2} .z -^{3}perx^{6}.y ^{2}.z)^{3} [/tex] tolong guyss
Matematika
sukma300
Pertanyaan
[tex](x.y ^{2} .z -^{3}perx^{6}.y ^{2}.z)^{3} [/tex]
tolong guyss
1 Jawaban
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1. Jawaban Anonyme
jawab
bilangan berpangkat
{ (x. y². z⁻³ ) / (x⁶. y². z) }³ =
= ( x.. x⁻⁶, y².y² . z⁻³.z)³
= (x⁻⁵. y⁰. z⁻²)³
= (x⁻⁵. z⁻²)³
= x⁻¹⁵. z⁻⁶
= 1/ (x¹⁵.z⁶)