Matematika

Pertanyaan


[tex](x.y ^{2} .z -^{3}perx^{6}.y ^{2}.z)^{3} [/tex]
tolong guyss

1 Jawaban

  • jawab
    bilangan berpangkat

    { (x. y². z⁻³ ) / (x⁶. y². z) }³ =

    = ( x.. x⁻⁶, y².y² . z⁻³.z)³

    = (x⁻⁵. y⁰. z⁻²)³

    = (x⁻⁵. z⁻²)³

    = x⁻¹⁵. z⁻⁶

    = 1/ (x¹⁵.z⁶)

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