simpangan baku dari data diatas 5,4,6,3,2,10 adalah

jawab
statistik

xi = 5,4,6,3,2,10
n = 6
∑xi= 5+4+6+3+2+10 = 30

X=1/n  ∑xi =  30/6 = 5

s² = 1/n ∑(xi  - X)²
s² = 1/6 {(5-5)²+(4-5)²+(6-5)²+(3-5)²+(2-5)²+(10-5)²
s² = 1/6 ( 0 +1 + 1+ 4+ 9+25)
s² = 1/6 (40) = 40/6 = 20/3

simpangan baku = s= √(s²) = √(20/3) = 2,58