Lim ->3 x-akar 2x+3/9-x2

jawab

Limit bentuk 0/0

limit  (x - √(2x + 3))/ (9 - x²)
x->3

limit  (x- √(2x + 3)) (x + √(2x+3)) / (3 -x)(3 + x)
x->3

limit  (x²-2x - 3)/ - (x - 3)(3 + x)
x->3

limit (x -3)(x + 1) / -(x - 3)(3+x)
x->3

limit  (x + 1)/ - (3 + x)
x->3
x= 3, limit = (3+1)/ - (3+3) = - 4/6 = -  2/3