Jika G(x) = 2 ∫ akar x dx = f(x) +c dengan f(x) = 2 akar x agar G(9) = 40 maka harga tetapan C sama dengan ...

g(x) = 2(2/3)x^3/2 +c = f(x) + c
maka f(x) =4/3 (x^3/2) = 2√x
x = 2 x 3/4
x = 3/2

g(9) = 40
40 = 4/3 ( 9^3/2) + c
40 = 4/3 x 3^2^3/2 + c
40 = 36+ c
c = 4