[tex] \frac{3 - \sqrt{2} }{3 + \sqrt{2 } } [/tex]
Matematika
adenur4
Pertanyaan
[tex] \frac{3 - \sqrt{2} }{3 + \sqrt{2 } } [/tex]
1 Jawaban
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1. Jawaban isnani18
[tex] \frac{3 - \sqrt{2} }{3 + \sqrt{2} } \\ = \frac{3 - \sqrt{2} }{3 + \sqrt{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} } \\ = \frac{9 - 3 \sqrt{2} - 3 \sqrt{2} + 2 }{9 - 3 \sqrt{2} + 3 \sqrt{2} - 2} \\ = \frac{9 - 6 \sqrt{2 } + 2 }{9 - 2} \\ = \frac{11 - 6 \sqrt{2} }{7} [/tex]