(2x-3)(2x^2+7x+6):4x^2-9
Matematika
saverojanus
Pertanyaan
(2x-3)(2x^2+7x+6):4x^2-9
1 Jawaban
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1. Jawaban iseonlz
[tex] \frac{(2x - 3)(2 {x}^{2} + 7x + 6)}{ {4x}^{2} - 9} = \\ = \frac{(2x - 3)(2 {x}^{2} + 7x + 6)}{(2x - 3)(2x + 3) } \\ = \frac{(2 {x}^{2} + 7x +6)}{(2x + 3)} \\ = \frac{(2x + 3)(x + 2)}{(2x + 3)} \\ = x + 2[/tex]