tolong bantuannya ya kak

jawab
peluang

4 keping uang logam --> n(S)= 2^4 = 16
A muncul 3A1G  --> (AAAG),(GAAA),AAGA),(AGAA)
n(A)= 4

P(A) = n(A)/nS)
fh (A) = n(A)/ n(S)  x  n
fH(A) = 4/16 x  32 = 8