tentukan 5 macam perbandingan trigonometri lainnya
Matematika
sinta953
Pertanyaan
tentukan 5 macam perbandingan trigonometri lainnya
1 Jawaban
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1. Jawaban ibrahimpataudi89
a.sin A = 3/4
sisi hadap (depan) = 3, sisi miring = 4, sisi samping = √ [4² - 3²] = √7
cos A = √7 / 4
tan A = 3 / √7 ⇒ 3√7 / 7
sec A = 1 / cos A = 4 / √7 ⇒ 4√7 / 7
cosec A = 1 / sin A = 4/3
cot A = 1 / tan A = √7 / 3
b.cot A = 8 / 15
sisi samping = 8, sisi hadap (depan) = 15, sisi miring = √ [8² + 15²] = 17
sin A = 15/17
cos A = 8/17
tan A = 15/8
sec A = 1 / cos A = 17/8
cosec A = 1 / sin A = 17/15
c.sec = 13/12
sisi miring = 13, sisi samping = 12, sisi hadap (depan) = √ [13² - 12²] = 5
sin A = 5/13
cos A = 12/13
tan A = 5/12
cosec A = 1 / sin A = 13/5
cot A = 1 / tan A = 12/5
d.tan α = 1 / √3
sisi hadap (depan) = 1, sisi samping = √3, sisi miring = √ [1² + (√3)²] = 2
sin α = 1/2
cos α = √3 / 2
sec α = 1 / cos α = 2 / √3 ⇒ 2√3 / 3
cosec α = 1 / sin α = 2
cot α = 1 / tan α = √3
e.sin α = 1 / √2
sisi hadap (depan) = 1, sisi miring = √2, sisi samping = √ [(√2)² - 1²] = 1
cos α = 1 / √2 ⇒ √2 / 2
tan α = 1
sec α = 1 / cos α = √2
cosec α = 1 / sin α = √2
cot α = 1 / tan α = 1
f.cos β = √3 / 2
sisi samping = √3, sisi miring = 2, sisi hadap (depan) = √ [2² - (√3)²] = 1
sin A = 1/2
tan A = 1 / √3 ⇒ √3 / 3
sec β = 1 / cos β = 2 / √3 ⇒ 2√3 / 3
cosec A = 1 / sin A = 2
cot A = 1 / tan A = √3