Matematika

Pertanyaan

tentukan 5 macam perbandingan trigonometri lainnya
tentukan 5 macam perbandingan trigonometri lainnya

1 Jawaban

  • a.sin A = 3/4
    sisi hadap (depan) = 3, sisi miring = 4, sisi samping = √ [4² - 3²] = √7
    cos A = √7 / 4
    tan A = 3 / √7 ⇒ 3√7 / 7
    sec A = 1 / cos A = 4 / √7 ⇒ 4√7 / 7
    cosec A = 1 / sin A = 4/3
    cot A = 1 / tan A = √7 / 3
     
    b.cot A = 8 / 15
    sisi samping = 8, sisi hadap (depan) = 15, sisi miring = √ [8² + 15²] = 17
    sin A = 15/17
    cos A = 8/17
    tan A = 15/8
    sec A = 1 / cos A = 17/8
    cosec A = 1 / sin A = 17/15

    c.sec = 13/12
    sisi miring = 13, sisi samping = 12, sisi hadap (depan) = √ [13² - 12²] = 5
    sin A = 5/13
    cos A = 12/13
    tan A = 5/12
    cosec A = 1 / sin A = 13/5
    cot A = 1 / tan A = 12/5

    d.tan α = 1 / √3
    sisi hadap (depan) = 1, sisi samping = √3, sisi miring = √ [1² + (√3)²] = 2
    sin α = 1/2
    cos α = √3 / 2
    sec α = 1 / cos α = 2 / √3 ⇒ 2√3 / 3
    cosec α = 1 / sin α = 2
    cot α = 1 / tan α = √3

    e.sin α = 1 / √2
    sisi hadap (depan) = 1, sisi miring = √2, sisi samping = √ [(√2)² - 1²] = 1
    cos α = 1 / √2 ⇒ √2 / 2
    tan α = 1
    sec α = 1 / cos α = √2
    cosec α = 1 / sin α = √2
    cot α = 1 / tan α = 1

    f.cos β = √3 / 2
    sisi samping = √3, sisi miring = 2, sisi hadap (depan) = √ [2² - (√3)²] = 1
    sin A = 1/2
    tan A = 1 / √3 ⇒ √3 / 3
    sec β = 1 / cos β = 2 / √3 ⇒ 2√3 / 3
    cosec A = 1 / sin A = 2
    cot A = 1 / tan A = √3