TOLONG DIJAWAB BESOK KUMPUL.
Matematika
kenzo2008
Pertanyaan
TOLONG DIJAWAB BESOK KUMPUL.
1 Jawaban
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1. Jawaban berlyantanggita
maaf kalau caranya salah
6.
[tex]4 \frac{1}{3} - 1 \frac{2}{6} \\ = (4 - 1) + ( \frac{1}{3} - \frac{2}{6} ) \\ = 3 + ( \frac{2}{6} - \frac{2}{6} ) \\ = 3 + 0 \\ = 3[/tex]
7.
[tex]2 \frac{1}{3} - 1 \frac{2}{9} \\ = (2 -1) + ( \frac{1}{3} - \frac{2}{9}) \\ = 1 + ( \frac{3}{9} - \frac{2}{9} ) \\ = 1 + \frac{1}{9} \\ = 1 \frac{1}{9} [/tex]
8.
[tex]2 \frac{2}{6} - 1 \frac{1}{2} \\ = (2 - 1) + ( \frac{2}{6} - \frac{1}{2} ) \\ = 1 + ( \frac{2}{6} - \frac{3}{6} ) \\ = - 1 \frac{1}{6} [/tex]
9.
[tex]3 \frac{4}{6} - 1 \frac{5}{12} \\ = (3 - 1) + ( \frac{4}{6} - \frac{5}{12} ) \\ = 2 + ( \frac{8}{12} - \frac{5}{12} ) \\ = 2 \frac{3}{12} \\ = 2 \frac{1}{4} [/tex]
10.
[tex]2 \frac{2}{4} - 1 \frac{1}{8} \\ = (2 - 1) + ( \frac{2}{4} - \frac{1}{8} ) \\ = 1 + ( \frac{4}{8} - \frac{1}{8} ) \\ = 1 \frac{3}{8} [/tex]