tentukan nilai limit fungsi berikut! a.lim x mendekati tak terhingga (√2x²+4x+1-√2x²-x+5). b.lim x mendekati tak yerhingga (√x²+2x+3-√x²+x-5) c.lim x mendekati

jawab

a. limit (x -> ~) (√ (2x²+ 4x +1) - (√2x² - x + 5)
a= p= 2
b = 4 
q= -1
Limit = b-q/2√a = (4 +1)/ 2√2 = 5/ 2√2  =  (5/2)√2

b. limit(x -> ~) (√(x² + 2x + 3) - (√(x² +x - 5)
a= p = 1
b = 2
q = 1
limit = b - q/ 2√a
limit = (2 - 1)/ 2√1 = 1/2 

c. limit(x-> ~) (√(9x² + 2x ) - (√(9x² -1)
a= p = 9
b = 2
q = 0
limit = b - q / 2√a = (2-0)/ 2√9= 2/2.3  = 1/3

d. limit (x -> ~) (√(x +3)² - √(x² -2x + 3)
a= p
b = 6
q= -2
limit = b- q/ 2√ a = (6+ 2)/ (2√1) = 8/2 = 4