Tolong jawab pertanyaan nya

[tex] \frac{3}{2} + \frac{40}{100} \times \frac{3}{10} \div \frac{1}{9} \\ = \frac{3}{2} + \frac{120}{1000} \div \frac{1}{9} \\ = \frac{3}{2} + \frac{12}{100} \div \frac{1}{9} \\ = \frac{3}{2} + \frac{12}{100} \times \frac{9}{1} \\ = \frac{3}{2} + \frac{108}{100} \\ = \frac{150}{100} + \frac{108}{100} \\ = \frac{258}{100} \\ = 2 \frac{58}{100} \\ = 2\frac{29}{50} [/tex]