hitunglah ph larutan NH4OH 0,011 M (Kb=1,1x10-4

[tex]9 + log 1.1[/tex]

OH- = akar Kb Mb
= akar 11.10^-5 x 11.10^-3
= akar 11 x 11.10^-8
= 11.10^-4 M

pOH = 4 - log 11
pH = 10 + log 11

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