jawab plis......... [tex]2 \sqrt{27} \times \sqrt{32} \div \sqrt{48} = [/tex]

[tex] = 2 \sqrt{27} \times \sqrt{32} \div \sqrt{48} \\ = 2 \sqrt{9 \times 3} \times \sqrt{16 \times 2} \div \sqrt{16 \times 3} \\ = 6 \sqrt{3} \times 4 \sqrt{2} \div 4 \sqrt{3} \\ = 24 \sqrt{6} \div 4 \sqrt{3} \\ = 6 \sqrt{2} [/tex]