Ubah menjadi pangkat positif A (1/4)-³ B 9- 3/4

a.
[tex]({ \frac{1}{4}})^{ - 3} = \frac{ {1}^{ - 3} }{ {4}^{ - 3} } = \frac{ {4}^{3} }{ {1}^{3} } = {4}^{3} = 64[/tex]
b.
[tex] {9}^{ - \frac{3}{4} } = \frac{1}{ {9}^{ \frac{3}{4} } } = \frac{1}{ { ({3}^{2}) }^{ \frac{3}{4} } } = \frac{1}{ { ({3}) }^{ 2 \times \frac{3}{4} } } = \frac{1}{ {3}^{ \frac{3}{2} } } = \frac{1}{3 \sqrt{3} } [/tex]
semoga bermanfaat dan jelas